25 Ml of Bulgur to Pounds Conversion

Question:
How many pounds of bulgur in 25 milliliters? How much are 25 ml of bulgur in pounds?

The answer is:
25 milliliters of bulgur is equivalent to 0.0443 pound(*)

Volume to 'Weight' Converter

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Results:

25 milliliters of bulgur equals 0.0443 pound. (*)
(*) To be more precise, 25 milliliters of bulgur is equal to 0.044258 pound. All figures are approximate.

Milliliters of bulgur to pounds Chart

Milliliters of bulgur to pounds
16 milliliters of bulgur = 0.0283 pound
17 milliliters of bulgur = 0.0301 pound
18 milliliters of bulgur = 0.0319 pound
19 milliliters of bulgur = 0.0336 pound
20 milliliters of bulgur = 0.0354 pound
21 milliliters of bulgur = 0.0372 pound
22 milliliters of bulgur = 0.0389 pound
23 milliliters of bulgur = 0.0407 pound
24 milliliters of bulgur = 0.0425 pound
25 milliliters of bulgur = 0.0443 pound
Milliliters of bulgur to pounds
25 milliliters of bulgur = 0.0443 pound
26 milliliters of bulgur = 0.046 pound
27 milliliters of bulgur = 0.0478 pound
28 milliliters of bulgur = 0.0496 pound
29 milliliters of bulgur = 0.0513 pound
30 milliliters of bulgur = 0.0531 pound
31 milliliters of bulgur = 0.0549 pound
32 milliliters of bulgur = 0.0566 pound
33 milliliters of bulgur = 0.0584 pound
34 milliliters of bulgur = 0.0602 pound

Note: some values may be rounded.

FAQs on bulgur weight to volume conversion

25 milliliters of bulgur equals how many pounds?

25 milliliters of bulgur is equivalent 0.0443 pound.

How much is 0.0443 pound of bulgur in milliliters?

0.0443 pound of bulgur equals 25 milliliters.

Weight to Volume Conversions - Cooking Ingredients

References:

  1. Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

Disclaimer

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