35 Ml of Raisins to Kg Conversion

Question:
How many kilograms of raisins in 35 milliliters? How much are 35 ml of raisins in kg?

The answer is:
35 milliliters of raisins is equivalent to 0.0235 kilogram(*)

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Results:

35 milliliters of raisins equals 0.0235 kilogram. (*)
(*) To be more precise, 35 milliliters of raisins is equal to 0.02352 kilogram. All figures are approximate.

Milliliters of raisins to kilograms Chart

Milliliters of raisins to kilograms
26 milliliters of raisins = 0.0175 kilogram
27 milliliters of raisins = 0.0181 kilogram
28 milliliters of raisins = 0.0188 kilogram
29 milliliters of raisins = 0.0195 kilogram
30 milliliters of raisins = 0.0202 kilogram
31 milliliters of raisins = 0.0208 kilogram
32 milliliters of raisins = 0.0215 kilogram
33 milliliters of raisins = 0.0222 kilogram
34 milliliters of raisins = 0.0228 kilogram
35 milliliters of raisins = 0.0235 kilogram
Milliliters of raisins to kilograms
35 milliliters of raisins = 0.0235 kilogram
36 milliliters of raisins = 0.0242 kilogram
37 milliliters of raisins = 0.0249 kilogram
38 milliliters of raisins = 0.0255 kilogram
39 milliliters of raisins = 0.0262 kilogram
40 milliliters of raisins = 0.0269 kilogram
41 milliliters of raisins = 0.0276 kilogram
42 milliliters of raisins = 0.0282 kilogram
43 milliliters of raisins = 0.0289 kilogram
44 milliliters of raisins = 0.0296 kilogram

Note: some values may be rounded.

FAQs on raisins weight to volume conversion

35 milliliters of raisins equals how many kilograms?

35 milliliters of raisins is equivalent 0.0235 kilogram.

How much is 0.0235 kilogram of raisins in milliliters?

0.0235 kilogram of raisins equals 35 milliliters.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

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