35 Ml of Ricotta to Pounds Conversion
Question:
How many pounds of ricotta in 35 milliliters? How much are 35 ml of ricotta in pounds?
The answer is:
35 milliliters of ricotta is equivalent to 0.0816 pounds(*)
Volume to 'Weight' Converter
Milliliters of ricotta to pounds Chart
Milliliters of ricotta to pounds | ||
---|---|---|
26 milliliters of ricotta | = | 0.0606 pounds |
27 milliliters of ricotta | = | 0.0629 pounds |
28 milliliters of ricotta | = | 0.0652 pounds |
29 milliliters of ricotta | = | 0.0676 pounds |
30 milliliters of ricotta | = | 0.0699 pounds |
31 milliliters of ricotta | = | 0.0722 pounds |
32 milliliters of ricotta | = | 0.0746 pounds |
33 milliliters of ricotta | = | 0.0769 pounds |
34 milliliters of ricotta | = | 0.0792 pounds |
35 milliliters of ricotta | = | 0.0816 pounds |
Milliliters of ricotta to pounds | ||
---|---|---|
35 milliliters of ricotta | = | 0.0816 pounds |
36 milliliters of ricotta | = | 0.0839 pounds |
37 milliliters of ricotta | = | 0.0862 pounds |
38 milliliters of ricotta | = | 0.0886 pounds |
39 milliliters of ricotta | = | 0.0909 pounds |
40 milliliters of ricotta | = | 0.0932 pounds |
41 milliliters of ricotta | = | 0.0955 pounds |
42 milliliters of ricotta | = | 0.0979 pounds |
43 milliliters of ricotta | = | 0.1 pounds |
44 milliliters of ricotta | = | 0.103 pounds |
Note: some values may be rounded.
FAQs on ricotta weight to volume conversion
35 milliliters of ricotta equals how many pounds?
35 milliliters of ricotta is equivalent 0.0816 pounds.
How much is 0.0816 pounds of ricotta in milliliters?
0.0816 pounds of ricotta equals 35 milliliters.
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.