35 Ml of Semolina to Pounds Conversion

Question:
How many pounds of semolina in 35 milliliters? How much are 35 ml of semolina in pounds?

The answer is:
35 milliliters of semolina is equivalent to 0.0587 pounds(*)

Volume to 'Weight' Converter

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Results:

35 milliliters of semolina equals 0.0587 pounds. (*)
(*) To be more precise, 35 milliliters of semolina is equal to 0.05872 pounds. All figures are approximate.

Milliliters of semolina to pounds Chart

Milliliters of semolina to pounds
26 milliliters of semolina = 0.0436 pounds
27 milliliters of semolina = 0.0453 pounds
28 milliliters of semolina = 0.047 pounds
29 milliliters of semolina = 0.0487 pounds
30 milliliters of semolina = 0.0503 pounds
31 milliliters of semolina = 0.052 pounds
32 milliliters of semolina = 0.0537 pounds
33 milliliters of semolina = 0.0554 pounds
34 milliliters of semolina = 0.057 pounds
35 milliliters of semolina = 0.0587 pounds
Milliliters of semolina to pounds
35 milliliters of semolina = 0.0587 pounds
36 milliliters of semolina = 0.0604 pounds
37 milliliters of semolina = 0.0621 pounds
38 milliliters of semolina = 0.0638 pounds
39 milliliters of semolina = 0.0654 pounds
40 milliliters of semolina = 0.0671 pounds
41 milliliters of semolina = 0.0688 pounds
42 milliliters of semolina = 0.0705 pounds
43 milliliters of semolina = 0.0721 pounds
44 milliliters of semolina = 0.0738 pounds

Note: some values may be rounded.

FAQs on semolina weight to volume conversion

35 milliliters of semolina equals how many pounds?

35 milliliters of semolina is equivalent 0.0587 pounds.

How much is 0.0587 pounds of semolina in milliliters?

0.0587 pounds of semolina equals 35 milliliters.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

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