5 Cups of Dry Lentils to Grams Conversion
Question:
How many grams of dry lentils in 5 US cups? How much are 5 cups of dry lentils in grams?
The answer is:
5 US cups of dry lentils is equivalent to 1000 grams(*)
Volume to 'Weight' Converter
US cups of dry lentils to grams Chart
| US cups of dry lentils to grams | ||
|---|---|---|
| 4.1 US cups of dry lentils | = | 820 grams |
| 4 1/5 US cups of dry lentils | = | 840 grams |
| 4.3 US cups of dry lentils | = | 860 grams |
| 4.4 US cups of dry lentils | = | 880 grams |
| 4 1/2 US cups of dry lentils | = | 900 grams |
| 4.6 US cups of dry lentils | = | 920 grams |
| 4.7 US cups of dry lentils | = | 940 grams |
| 4.8 US cups of dry lentils | = | 960 grams |
| 4.9 US cups of dry lentils | = | 980 grams |
| 5 US cups of dry lentils | = | 1000 grams |
| US cups of dry lentils to grams | ||
|---|---|---|
| 5 US cups of dry lentils | = | 1000 grams |
| 5.1 US cups of dry lentils | = | 1020 grams |
| 5 1/5 US cups of dry lentils | = | 1040 grams |
| 5.3 US cups of dry lentils | = | 1060 grams |
| 5.4 US cups of dry lentils | = | 1080 grams |
| 5 1/2 US cups of dry lentils | = | 1100 grams |
| 5.6 US cups of dry lentils | = | 1120 grams |
| 5.7 US cups of dry lentils | = | 1140 grams |
| 5.8 US cups of dry lentils | = | 1160 grams |
| 5.9 US cups of dry lentils | = | 1180 grams |
Note: some values may be rounded.
FAQs on dry lentils weight to volume conversion
5 US cups of dry lentils equals how many grams?
5 US cups of dry lentils is equivalent 1000 grams.
How much is 1000 grams of dry lentils in US cups?
1000 grams of dry lentils equals 5 ( ~ 5) US cups.
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.