5 Cups of Mint Leaves to Lb Conversion
Question:
How many pounds of mint leaves in 5 US cups? How much are 5 cups of mint leaves in lb?
The answer is:
5 US cups of mint leaves is equivalent to 0.331 ( ~
Volume to 'Weight' Converter
US cups of mint leaves to pounds Chart
US cups of mint leaves to pounds | ||
---|---|---|
4.1 US cups of mint leaves | = | 0.272 pounds |
4 1/5 US cups of mint leaves | = | 0.278 pounds |
4.3 US cups of mint leaves | = | 0.285 pounds |
4.4 US cups of mint leaves | = | 0.291 pounds |
4 1/2 US cups of mint leaves | = | 0.298 pounds |
4.6 US cups of mint leaves | = | 0.305 pounds |
4.7 US cups of mint leaves | = | 0.311 pounds |
4.8 US cups of mint leaves | = | 0.318 pounds |
4.9 US cups of mint leaves | = | 0.325 pounds |
5 US cups of mint leaves | = | 0.331 pounds |
US cups of mint leaves to pounds | ||
---|---|---|
5 US cups of mint leaves | = | 0.331 pounds |
5.1 US cups of mint leaves | = | 0.338 pounds |
5 1/5 US cups of mint leaves | = | 0.344 pounds |
5.3 US cups of mint leaves | = | 0.351 pounds |
5.4 US cups of mint leaves | = | 0.358 pounds |
5 1/2 US cups of mint leaves | = | 0.364 pounds |
5.6 US cups of mint leaves | = | 0.371 pounds |
5.7 US cups of mint leaves | = | 0.378 pounds |
5.8 US cups of mint leaves | = | 0.384 pounds |
5.9 US cups of mint leaves | = | 0.391 pounds |
Note: some values may be rounded.
FAQs on mint leaves weight to volume conversion
5 US cups of mint leaves equals how many pounds?
5 US cups of mint leaves is equivalent 0.331 ( ~
How much is 0.331 pounds of mint leaves in US cups?
0.331 pounds of mint leaves equals 5 ( ~ 5) US cups.
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.
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