5 Cups of Packed Mâche to Pounds Conversion

Question:
How many pounds of packed mâche in 5 US cups? How much are 5 cups of packed mâche in pounds?

The answer is:
5 US cups of packed mâche is equivalent to 0.222 ( ~ 1/4) pounds(*)

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Results:

5 US cups of packed mâche equals 0.222 ( ~ 1/4) pounds. (*)
(*) To be more precise, 5 US cups of packed mâche is equal to 0.22167 pounds. All figures are approximate.

US cups of packed mâche to pounds Chart

US cups of packed mâche to pounds
4.1 US cups of packed mâche = 0.182 pounds
1/5 US cups of packed mâche = 0.186 pounds
4.3 US cups of packed mâche = 0.191 pounds
4.4 US cups of packed mâche = 0.195 pounds
1/2 US cups of packed mâche = 0.2 pounds
4.6 US cups of packed mâche = 0.204 pounds
4.7 US cups of packed mâche = 0.208 pounds
4.8 US cups of packed mâche = 0.213 pounds
4.9 US cups of packed mâche = 0.217 pounds
5 US cups of packed mâche = 0.222 pounds
US cups of packed mâche to pounds
5 US cups of packed mâche = 0.222 pounds
5.1 US cups of packed mâche = 0.226 pounds
1/5 US cups of packed mâche = 0.231 pounds
5.3 US cups of packed mâche = 0.235 pounds
5.4 US cups of packed mâche = 0.239 pounds
1/2 US cups of packed mâche = 0.244 pounds
5.6 US cups of packed mâche = 0.248 pounds
5.7 US cups of packed mâche = 0.253 pounds
5.8 US cups of packed mâche = 0.257 pounds
5.9 US cups of packed mâche = 0.262 pounds

Note: some values may be rounded.

FAQs on packed mâche weight to volume conversion

5 US cups of packed mâche equals how many pounds?

5 US cups of packed mâche is equivalent 0.222 ( ~ 1/4) pounds.

How much is 0.222 pounds of packed mâche in US cups?

0.222 pounds of packed mâche equals 5 ( ~ 5) US cups.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

Disclaimer

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