5 Ml of Apricots to Pounds Conversion

Question:
How many pounds of apricots in 5 milliliters? How much are 5 ml of apricots in pounds?

The answer is:
5 milliliters of apricots is equivalent to 0.0105 pound(*)

Volume to 'Weight' Converter

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Results:

5 milliliters of apricots equals 0.0105 pound. (*)
(*) To be more precise, 5 milliliters of apricots is equal to 0.010483 pound. All figures are approximate.

Milliliters of apricots to pounds Chart

Milliliters of apricots to pounds
4.1 milliliters of apricots = 0.0086 pound
1/5 milliliters of apricots = 0.00881 pound
4.3 milliliters of apricots = 0.00902 pound
4.4 milliliters of apricots = 0.00923 pound
1/2 milliliters of apricots = 0.00943 pound
4.6 milliliters of apricots = 0.00964 pound
4.7 milliliters of apricots = 0.00985 pound
4.8 milliliters of apricots = 0.0101 pound
4.9 milliliters of apricots = 0.0103 pound
5 milliliters of apricots = 0.0105 pound
Milliliters of apricots to pounds
5 milliliters of apricots = 0.0105 pound
5.1 milliliters of apricots = 0.0107 pound
1/5 milliliters of apricots = 0.0109 pound
5.3 milliliters of apricots = 0.0111 pound
5.4 milliliters of apricots = 0.0113 pound
1/2 milliliters of apricots = 0.0115 pound
5.6 milliliters of apricots = 0.0117 pound
5.7 milliliters of apricots = 0.012 pound
5.8 milliliters of apricots = 0.0122 pound
5.9 milliliters of apricots = 0.0124 pound

Note: some values may be rounded.

FAQs on apricots weight to volume conversion

5 milliliters of apricots equals how many pounds?

5 milliliters of apricots is equivalent 0.0105 pound.

How much is 0.0105 pound of apricots in milliliters?

0.0105 pound of apricots equals 5 milliliters.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

Disclaimer

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