5 Ml of Vinegar to Pounds Conversion
Question:
How many pounds of vinegar in 5 milliliters? How much are 5 ml of vinegar in pounds?
The answer is:
5 milliliters of vinegar is equivalent to 0.0107 pound(*)
Volume to 'Weight' Converter
Milliliters of vinegar to pounds Chart
Milliliters of vinegar to pounds | ||
---|---|---|
4.1 milliliters of vinegar | = | 0.00879 pound |
4 1/5 milliliters of vinegar | = | 0.009 pound |
4.3 milliliters of vinegar | = | 0.00921 pound |
4.4 milliliters of vinegar | = | 0.00943 pound |
4 1/2 milliliters of vinegar | = | 0.00964 pound |
4.6 milliliters of vinegar | = | 0.00986 pound |
4.7 milliliters of vinegar | = | 0.0101 pound |
4.8 milliliters of vinegar | = | 0.0103 pound |
4.9 milliliters of vinegar | = | 0.0105 pound |
5 milliliters of vinegar | = | 0.0107 pound |
Milliliters of vinegar to pounds | ||
---|---|---|
5 milliliters of vinegar | = | 0.0107 pound |
5.1 milliliters of vinegar | = | 0.0109 pound |
5 1/5 milliliters of vinegar | = | 0.0111 pound |
5.3 milliliters of vinegar | = | 0.0114 pound |
5.4 milliliters of vinegar | = | 0.0116 pound |
5 1/2 milliliters of vinegar | = | 0.0118 pound |
5.6 milliliters of vinegar | = | 0.012 pound |
5.7 milliliters of vinegar | = | 0.0122 pound |
5.8 milliliters of vinegar | = | 0.0124 pound |
5.9 milliliters of vinegar | = | 0.0126 pound |
Note: some values may be rounded.
FAQs on vinegar weight to volume conversion
5 milliliters of vinegar equals how many pounds?
5 milliliters of vinegar is equivalent 0.0107 pound.
How much is 0.0107 pound of vinegar in milliliters?
0.0107 pound of vinegar equals 5 milliliters.
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.
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