500 Ml of Vinegar to Pounds Conversion
Question:
How many pounds of vinegar in 500 milliliters? How much are 500 ml of vinegar in pounds?
The answer is:
500 milliliters of vinegar is equivalent to 1.07 ( ~ 1) pounds(*)
Volume to 'Weight' Converter
Milliliters of vinegar to pounds Chart
Milliliters of vinegar to pounds | ||
---|---|---|
410 milliliters of vinegar | = | 0.879 pounds |
420 milliliters of vinegar | = | 0.9 pounds |
430 milliliters of vinegar | = | 0.921 pounds |
440 milliliters of vinegar | = | 0.943 pounds |
450 milliliters of vinegar | = | 0.964 pounds |
460 milliliters of vinegar | = | 0.986 pounds |
470 milliliters of vinegar | = | 1.01 pounds |
480 milliliters of vinegar | = | 1.03 pounds |
490 milliliters of vinegar | = | 1.05 pounds |
500 milliliters of vinegar | = | 1.07 pounds |
Milliliters of vinegar to pounds | ||
---|---|---|
500 milliliters of vinegar | = | 1.07 pounds |
510 milliliters of vinegar | = | 1.09 pounds |
520 milliliters of vinegar | = | 1.11 pounds |
530 milliliters of vinegar | = | 1.14 pounds |
540 milliliters of vinegar | = | 1.16 pounds |
550 milliliters of vinegar | = | 1.18 pounds |
560 milliliters of vinegar | = | 1.2 pounds |
570 milliliters of vinegar | = | 1.22 pounds |
580 milliliters of vinegar | = | 1.24 pounds |
590 milliliters of vinegar | = | 1.26 pounds |
Note: some values may be rounded.
FAQs on vinegar weight to volume conversion
500 milliliters of vinegar equals how many pounds?
500 milliliters of vinegar is equivalent 1.07 ( ~ 1) pounds.
How much is 1.07 pounds of vinegar in milliliters?
1.07 pounds of vinegar equals 500 milliliters.
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.