A Eighth Teaspoons of Potato to Grams Conversion

Question:
How many grams of potato in A Eighth US teaspoons? How much is A Eighth teaspoons of potato in grams?

The answer is:
a eighth US teaspoons of potato is equivalent to 0.364 grams(*)

Volume to 'Weight' Converter

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Results:

a eighth US teaspoons of potato equals 0.364 grams. (*)
(*) To be more precise, a eighth US teaspoons of potato is equal to 0.36351 grams. All figures are approximate.

US teaspoons of potato to grams Chart

US teaspoons of potato to grams
0.035 US teaspoons of potato = 0.102 grams
0.045 US teaspoons of potato = 0.131 grams
0.055 US teaspoons of potato = 0.16 grams
0.065 US teaspoons of potato = 0.189 grams
0.075 US teaspoons of potato = 0.218 grams
0.085 US teaspoons of potato = 0.247 grams
0.095 US teaspoons of potato = 0.276 grams
0.105 US teaspoons of potato = 0.305 grams
0.115 US teaspoons of potato = 0.334 grams
1/8 US teaspoons of potato = 0.364 grams
US teaspoons of potato to grams
1/8 US teaspoons of potato = 0.364 grams
0.135 US teaspoons of potato = 0.393 grams
0.145 US teaspoons of potato = 0.422 grams
0.155 US teaspoons of potato = 0.451 grams
0.165 US teaspoons of potato = 0.48 grams
0.175 US teaspoons of potato = 0.509 grams
0.185 US teaspoons of potato = 0.538 grams
0.195 US teaspoons of potato = 0.567 grams
0.205 US teaspoons of potato = 0.596 grams
0.215 US teaspoons of potato = 0.625 grams

Note: some values may be rounded.

FAQs on potato weight to volume conversion

A eighth US teaspoons of potato equals how many grams?

A eighth US teaspoons of potato is equivalent 0.364 grams.

How much is 0.364 grams of potato in US teaspoons?

0.364 grams of potato equals a eighth ( ~ 1/4) US teaspoons.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

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