A Fifth Cups of Bulgur to Pounds Conversion

Question:
How many pounds of bulgur in A Fifth US cups? How much is A Fifth cups of bulgur in pounds?

The answer is:
a fifth US cups of bulgur is equivalent to 0.0838 pounds^(*)

Volume to 'Weight' Converter

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Results: a fifth US cups of bulgur equals 0.0838 pounds. (*)
(*) To be more precise, a fifth US cups of bulgur is equal to 0.083767 pounds. All figures are approximate.

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US cups of bulgur to pounds Chart

US cups of bulgur to pounds
0.11 US cups of bulgur	=	0.0461 pounds
0.12 US cups of bulgur	=	0.0503 pounds
0.13 US cups of bulgur	=	0.0544 pounds
0.14 US cups of bulgur	=	0.0586 pounds
0.15 US cups of bulgur	=	0.0628 pounds
0.16 US cups of bulgur	=	0.067 pounds
0.17 US cups of bulgur	=	0.0712 pounds
0.18 US cups of bulgur	=	0.0754 pounds
0.19 US cups of bulgur	=	0.0796 pounds
¹/₅ US cups of bulgur	=	0.0838 pounds

US cups of bulgur to pounds
¹/₅ US cups of bulgur	=	0.0838 pounds
0.21 US cups of bulgur	=	0.088 pounds
0.22 US cups of bulgur	=	0.0921 pounds
0.23 US cups of bulgur	=	0.0963 pounds
0.24 US cups of bulgur	=	0.101 pounds
¹/₄ US cups of bulgur	=	0.105 pounds
0.26 US cups of bulgur	=	0.109 pounds
0.27 US cups of bulgur	=	0.113 pounds
0.28 US cups of bulgur	=	0.117 pounds
0.29 US cups of bulgur	=	0.121 pounds

Note: some values may be rounded.

FAQs on bulgur weight to volume conversion

A fifth US cups of bulgur equals how many pounds?

A fifth US cups of bulgur is equivalent 0.0838 pounds.

How much is 0.0838 pounds of bulgur in US cups?

0.0838 pounds of bulgur equals a fifth ( ~ ¹/₄) US cups.

Weight to Volume Conversions - Cooking Ingredients

References:

Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.