A Fifth Cups of Cheese to Pounds Conversion

Question:
How many pounds of cheese in A Fifth US cups? How much is A Fifth cups of cheese in pounds?

The answer is:
a fifth US cups of cheese is equivalent to 0.0992 pounds(*)

Volume to 'Weight' Converter

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Results:

a fifth US cups of cheese equals 0.0992 pounds. (*)
(*) To be more precise, a fifth US cups of cheese is equal to 0.099206 pounds. All figures are approximate.

US cups of cheese to pounds Chart

US cups of cheese to pounds
0.11 US cups of cheese = 0.0546 pounds
0.12 US cups of cheese = 0.0595 pounds
0.13 US cups of cheese = 0.0645 pounds
0.14 US cups of cheese = 0.0694 pounds
0.15 US cups of cheese = 0.0744 pounds
0.16 US cups of cheese = 0.0794 pounds
0.17 US cups of cheese = 0.0843 pounds
0.18 US cups of cheese = 0.0893 pounds
0.19 US cups of cheese = 0.0942 pounds
1/5 US cups of cheese = 0.0992 pounds
US cups of cheese to pounds
1/5 US cups of cheese = 0.0992 pounds
0.21 US cups of cheese = 0.104 pounds
0.22 US cups of cheese = 0.109 pounds
0.23 US cups of cheese = 0.114 pounds
0.24 US cups of cheese = 0.119 pounds
1/4 US cups of cheese = 0.124 pounds
0.26 US cups of cheese = 0.129 pounds
0.27 US cups of cheese = 0.134 pounds
0.28 US cups of cheese = 0.139 pounds
0.29 US cups of cheese = 0.144 pounds

Note: some values may be rounded.

FAQs on cheese weight to volume conversion

A fifth US cups of cheese equals how many pounds?

A fifth US cups of cheese is equivalent 0.0992 pounds.

How much is 0.0992 pounds of cheese in US cups?

0.0992 pounds of cheese equals a fifth ( ~ 1/4) US cups.

Weight to Volume Conversions - Cooking Ingredients

References:

  1. Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

Disclaimer

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