A Fifth Teaspoons of Oats to Grams Conversion

Question:
How many grams of oats in A Fifth US teaspoons? How much is A Fifth teaspoons of oats in grams?

The answer is:
a fifth US teaspoons of oats is equivalent to 0.65 grams(*)

Volume to 'Weight' Converter

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Results:

a fifth US teaspoons of oats equals 0.65 grams. (*)
(*) To be more precise, a fifth US teaspoons of oats is equal to 0.64963 grams. All figures are approximate.

US teaspoons of oats to grams Chart

US teaspoons of oats to grams
0.11 US teaspoons of oats = 0.357 grams
0.12 US teaspoons of oats = 0.39 grams
0.13 US teaspoons of oats = 0.422 grams
0.14 US teaspoons of oats = 0.455 grams
0.15 US teaspoons of oats = 0.487 grams
0.16 US teaspoons of oats = 0.52 grams
0.17 US teaspoons of oats = 0.552 grams
0.18 US teaspoons of oats = 0.585 grams
0.19 US teaspoons of oats = 0.617 grams
1/5 US teaspoons of oats = 0.65 grams
US teaspoons of oats to grams
1/5 US teaspoons of oats = 0.65 grams
0.21 US teaspoons of oats = 0.682 grams
0.22 US teaspoons of oats = 0.715 grams
0.23 US teaspoons of oats = 0.747 grams
0.24 US teaspoons of oats = 0.78 grams
1/4 US teaspoons of oats = 0.812 grams
0.26 US teaspoons of oats = 0.845 grams
0.27 US teaspoons of oats = 0.877 grams
0.28 US teaspoons of oats = 0.909 grams
0.29 US teaspoons of oats = 0.942 grams

Note: some values may be rounded.

FAQs on oats weight to volume conversion

A fifth US teaspoons of oats equals how many grams?

A fifth US teaspoons of oats is equivalent 0.65 grams.

How much is 0.65 grams of oats in US teaspoons?

0.65 grams of oats equals a fifth ( ~ 1/4) US teaspoons.

Weight to Volume Conversions - Cooking Ingredients

References:

  1. Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

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