A Fifth Tsp of Vinegar to Grams Conversion
Question:
How many grams of vinegar in A Fifth US teaspoons? How much is A Fifth tsp of vinegar in grams?
The answer is:
a fifth US teaspoons of vinegar is equivalent to 0.958 grams(*)
Volume to 'Weight' Converter
US teaspoons of vinegar to grams Chart
US teaspoons of vinegar to grams | ||
---|---|---|
0.11 US teaspoons of vinegar | = | 0.527 grams |
0.12 US teaspoons of vinegar | = | 0.575 grams |
0.13 US teaspoons of vinegar | = | 0.623 grams |
0.14 US teaspoons of vinegar | = | 0.671 grams |
0.15 US teaspoons of vinegar | = | 0.719 grams |
0.16 US teaspoons of vinegar | = | 0.767 grams |
0.17 US teaspoons of vinegar | = | 0.814 grams |
0.18 US teaspoons of vinegar | = | 0.862 grams |
0.19 US teaspoons of vinegar | = | 0.91 grams |
1/5 US teaspoons of vinegar | = | 0.958 grams |
US teaspoons of vinegar to grams | ||
---|---|---|
1/5 US teaspoons of vinegar | = | 0.958 grams |
0.21 US teaspoons of vinegar | = | 1.01 grams |
0.22 US teaspoons of vinegar | = | 1.05 grams |
0.23 US teaspoons of vinegar | = | 1.1 grams |
0.24 US teaspoons of vinegar | = | 1.15 grams |
1/4 US teaspoons of vinegar | = | 1.2 grams |
0.26 US teaspoons of vinegar | = | 1.25 grams |
0.27 US teaspoons of vinegar | = | 1.29 grams |
0.28 US teaspoons of vinegar | = | 1.34 grams |
0.29 US teaspoons of vinegar | = | 1.39 grams |
Note: some values may be rounded.
FAQs on vinegar weight to volume conversion
A fifth US teaspoons of vinegar equals how many grams?
A fifth US teaspoons of vinegar is equivalent 0.958 grams.
How much is 0.958 grams of vinegar in US teaspoons?
0.958 grams of vinegar equals a fifth ( ~
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.
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