Half Cup of Baking Powder to Grams Conversion

Question:
How many grams of baking powder in Half US cup? How much is Half cup of baking powder in grams?

The answer is:
half US cup of baking powder is equivalent to 115 grams(*)

Volume to 'Weight' Converter

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Results:

half US cup of baking powder equals 115 grams. (*)
(*) To be more precise, half US cup of baking powder is equal to 114.98 grams. All figures are approximate.

US cups of baking powder to grams Chart

US cups of baking powder to grams
0.41 US cup of baking powder = 94.3 grams
0.42 US cup of baking powder = 96.6 grams
0.43 US cup of baking powder = 98.9 grams
0.44 US cup of baking powder = 101 grams
0.45 US cup of baking powder = 103 grams
0.46 US cup of baking powder = 106 grams
0.47 US cup of baking powder = 108 grams
0.48 US cup of baking powder = 110 grams
0.49 US cup of baking powder = 113 grams
1/2 US cup of baking powder = 115 grams
US cups of baking powder to grams
1/2 US cup of baking powder = 115 grams
0.51 US cup of baking powder = 117 grams
0.52 US cup of baking powder = 120 grams
0.53 US cup of baking powder = 122 grams
0.54 US cup of baking powder = 124 grams
0.55 US cup of baking powder = 126 grams
0.56 US cup of baking powder = 129 grams
0.57 US cup of baking powder = 131 grams
0.58 US cup of baking powder = 133 grams
0.59 US cup of baking powder = 136 grams

Note: some values may be rounded.

FAQs on baking powder weight to volume conversion

Half US cup of baking powder equals how many grams?

Half US cup of baking powder is equivalent 115 grams.

How much is 115 grams of baking powder in US cups?

115 grams of baking powder equals half ( ~ 1/2) US cup.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

Disclaimer

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