1/2 Pounds of Bulgur to Ml Conversion

Questions: How many milliliters of bulgur in 1/2 pounds? How much is 1/2 pounds of bulgur in ml?

The answer is: 1/2 pounds of bulgur is equivalent to 282 milliliters(*)

'Weight' to Volume Converter

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Results
1/2 pounds of bulgur equals 282 milliliters.
(*) To be more precise, 1/2 pounds of bulgur is equal to 282.44 milliliters. All figures are approximate.

Pounds of bulgur to milliliters Chart

Pounds of bulgur to milliliters
0.41 pounds of bulgur = 232 milliliters
0.42 pounds of bulgur = 237 milliliters
0.43 pounds of bulgur = 243 milliliters
0.44 pounds of bulgur = 249 milliliters
0.45 pounds of bulgur = 254 milliliters
0.46 pounds of bulgur = 260 milliliters
0.47 pounds of bulgur = 265 milliliters
0.48 pounds of bulgur = 271 milliliters
0.49 pounds of bulgur = 277 milliliters
1/2 pounds of bulgur = 282 milliliters
Pounds of bulgur to milliliters
1/2 pounds of bulgur = 282 milliliters
0.51 pounds of bulgur = 288 milliliters
0.52 pounds of bulgur = 294 milliliters
0.53 pounds of bulgur = 299 milliliters
0.54 pounds of bulgur = 305 milliliters
0.55 pounds of bulgur = 311 milliliters
0.56 pounds of bulgur = 316 milliliters
0.57 pounds of bulgur = 322 milliliters
0.58 pounds of bulgur = 328 milliliters
0.59 pounds of bulgur = 333 milliliters

Note: some values may be rounded.

FAQs on bulgur volume to weight conversion

1/2 pounds of bulgur equals how many milliliters?

1/2 pounds of bulgur is equivalent 282 milliliters.

How much is 282 milliliters of bulgur in pounds?

282 milliliters of bulgur equals 1/2 ( ~ 1/2) pounds.

Weight to Volume Conversions - Cooking Ingredients

References:

  1. Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

Disclaimer

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