1 1/2 Pounds of Sugar to Ml Conversion

Questions: How many milliliters of sugar in 1 1/2 pounds? How much are 1 1/2 pounds of sugar in ml?

The answer is: 1 1/2 pounds of sugar is equivalent to 800 milliliters(*)

'Weight' to Volume Converter

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Results
1 1/2 pounds of sugar equals 800 milliliters.
(*) To be more precise, 1 1/2 pounds of sugar is equal to 800.46 milliliters. All figures are approximate.

Pounds of sugar to milliliters Chart

Pounds of sugar to milliliters
0.6 pounds of sugar = 320 milliliters
0.7 pounds of sugar = 374 milliliters
0.8 pounds of sugar = 427 milliliters
0.9 pounds of sugar = 480 milliliters
1 pound of sugar = 534 milliliters
1.1 pounds of sugar = 587 milliliters
1 1/5 pounds of sugar = 640 milliliters
1.3 pounds of sugar = 694 milliliters
1.4 pounds of sugar = 747 milliliters
1 1/2 pounds of sugar = 800 milliliters
Pounds of sugar to milliliters
1 1/2 pounds of sugar = 800 milliliters
1.6 pounds of sugar = 854 milliliters
1.7 pounds of sugar = 907 milliliters
1.8 pounds of sugar = 961 milliliters
1.9 pounds of sugar = 1010 milliliters
2 pounds of sugar = 1070 milliliters
2.1 pounds of sugar = 1120 milliliters
2 1/5 pounds of sugar = 1170 milliliters
2.3 pounds of sugar = 1230 milliliters
2.4 pounds of sugar = 1280 milliliters

Note: some values may be rounded.

FAQs on sugar volume to weight conversion

1 1/2 pounds of sugar equals how many milliliters?

1 1/2 pounds of sugar is equivalent 800 milliliters.

How much is 800 milliliters of sugar in pounds?

800 milliliters of sugar equals 1 1/2 ( ~ 1 1/2) pounds.

Weight to Volume Conversions - Cooking Ingredients

References:

  1. Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

Disclaimer

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