1 1/3 Pounds of Vinegar to Ml Conversion
Questions: How many milliliters of vinegar in 1 1/3 pound? How much are 1 1/3 pound of vinegar in ml?
The answer is: 1 1/3 pound of vinegar is equivalent to 622 milliliters(*)
'Weight' to Volume Converter
Pounds of vinegar to milliliters Chart
Pounds of vinegar to milliliters | ||
---|---|---|
0.433 pound of vinegar | = | 202 milliliters |
0.533 pound of vinegar | = | 249 milliliters |
0.633 pound of vinegar | = | 295 milliliters |
0.733 pound of vinegar | = | 342 milliliters |
0.833 pound of vinegar | = | 389 milliliters |
0.933 pound of vinegar | = | 435 milliliters |
1.033 pound of vinegar | = | 482 milliliters |
1.133 pound of vinegar | = | 529 milliliters |
1.233 pound of vinegar | = | 575 milliliters |
1.33 pound of vinegar | = | 622 milliliters |
Pounds of vinegar to milliliters | ||
---|---|---|
1.33 pound of vinegar | = | 622 milliliters |
1.433 pound of vinegar | = | 669 milliliters |
1.533 pound of vinegar | = | 715 milliliters |
1.633 pound of vinegar | = | 762 milliliters |
1.733 pound of vinegar | = | 809 milliliters |
1.833 pound of vinegar | = | 855 milliliters |
1.933 pound of vinegar | = | 902 milliliters |
2.033 pounds of vinegar | = | 949 milliliters |
2.133 pounds of vinegar | = | 995 milliliters |
2.233 pounds of vinegar | = | 1040 milliliters |
Note: some values may be rounded.
FAQs on vinegar volume to weight conversion
1 1/3 pound of vinegar equals how many milliliters?
1 1/3 pound of vinegar is equivalent 622 milliliters.
How much is 622 milliliters of vinegar in pounds?
622 milliliters of vinegar equals 1 1/3 ( ~ 1
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.