1 2/3 Pounds of Ice Cream to Cups Conversion
Questions: How many US cups of ice cream in 1 2/3 pounds? How much are 1 2/3 pounds of ice cream in cups?
The answer is: 1 2/3 pounds of ice cream is equivalent to 5.04 ( ~ 5) US cups(*)
'Weight' to Volume Converter
Pounds of ice cream to US cups Chart
Pounds of ice cream to US cups | ||
---|---|---|
0.767 pounds of ice cream | = | 2.32 US cups |
0.867 pounds of ice cream | = | 2.62 US cups |
0.967 pounds of ice cream | = | 2.92 US cups |
1.067 pounds of ice cream | = | 3.23 US cups |
1.167 pounds of ice cream | = | 3.53 US cups |
1.267 pounds of ice cream | = | 3.83 US cups |
1.367 pounds of ice cream | = | 4.13 US cups |
1.467 pounds of ice cream | = | 4.44 US cups |
1.567 pounds of ice cream | = | 4.74 US cups |
1.67 pounds of ice cream | = | 5.04 US cups |
Pounds of ice cream to US cups | ||
---|---|---|
1.67 pounds of ice cream | = | 5.04 US cups |
1.767 pounds of ice cream | = | 5.34 US cups |
1.867 pounds of ice cream | = | 5.65 US cups |
1.967 pounds of ice cream | = | 5.95 US cups |
2.067 pounds of ice cream | = | 6.25 US cups |
2.167 pounds of ice cream | = | 6.55 US cups |
2.267 pounds of ice cream | = | 6.86 US cups |
2.367 pounds of ice cream | = | 7.16 US cups |
2.467 pounds of ice cream | = | 7.46 US cups |
2.567 pounds of ice cream | = | 7.76 US cups |
Note: some values may be rounded.
FAQs on ice cream volume to weight conversion
1 2/3 pounds of ice cream equals how many US cups?
1 2/3 pounds of ice cream is equivalent 5.04 ( ~ 5) US cups.
How much is 5.04 US cups of ice cream in pounds?
5.04 US cups of ice cream equals 1 2/3 ( ~ 1
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.