10 Grams of Apricots to Ml Conversion

Questions: How many milliliters of apricots in 10 grams? How much are 10 grams of apricots in ml?

The answer is: 10 grams of apricots is equivalent to 10.5 milliliters^(*)

'Weight' to Volume Converter

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Results
10 grams of apricots equals 10.5 milliliters.
(*) To be more precise, 10 grams of apricots is equal to 10.515 milliliters. All figures are approximate.
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Grams of apricots to milliliters Chart

Grams of apricots to milliliters
1 gram of apricots	=	1.05 milliliters
2 grams of apricots	=	2.1 milliliters
3 grams of apricots	=	3.15 milliliters
4 grams of apricots	=	4.21 milliliters
5 grams of apricots	=	5.26 milliliters
6 grams of apricots	=	6.31 milliliters
7 grams of apricots	=	7.36 milliliters
8 grams of apricots	=	8.41 milliliters
9 grams of apricots	=	9.46 milliliters
10 grams of apricots	=	10.5 milliliters

Grams of apricots to milliliters
10 grams of apricots	=	10.5 milliliters
11 grams of apricots	=	11.6 milliliters
12 grams of apricots	=	12.6 milliliters
13 grams of apricots	=	13.7 milliliters
14 grams of apricots	=	14.7 milliliters
15 grams of apricots	=	15.8 milliliters
16 grams of apricots	=	16.8 milliliters
17 grams of apricots	=	17.9 milliliters
18 grams of apricots	=	18.9 milliliters
19 grams of apricots	=	20 milliliters

Note: some values may be rounded.

FAQs on apricots volume to weight conversion

10 grams of apricots equals how many milliliters?

10 grams of apricots is equivalent 10.5 milliliters.

How much is 10.5 milliliters of apricots in grams?

10.5 milliliters of apricots equals 10 grams.

Weight to Volume Conversions - Cooking Ingredients

References:

Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.