15 Grams of Chopped Onion to Cups Conversion
Questions: How many US cups of chopped onion in 15 grams? How much are 15 grams of chopped onion in cups?
The answer is: 15 grams of chopped onion is equivalent to 0.288 ( ~
'Weight' to Volume Converter
Grams of chopped onion to US cups Chart
Grams of chopped onion to US cups | ||
---|---|---|
6 grams of chopped onion | = | 0.115 US cup |
7 grams of chopped onion | = | 0.134 US cup |
8 grams of chopped onion | = | 0.154 US cup |
9 grams of chopped onion | = | 0.173 US cup |
10 grams of chopped onion | = | 0.192 US cup |
11 grams of chopped onion | = | 0.211 US cup |
12 grams of chopped onion | = | 0.231 US cup |
13 grams of chopped onion | = | 0.25 US cup |
14 grams of chopped onion | = | 0.269 US cup |
15 grams of chopped onion | = | 0.288 US cup |
Grams of chopped onion to US cups | ||
---|---|---|
15 grams of chopped onion | = | 0.288 US cup |
16 grams of chopped onion | = | 0.307 US cup |
17 grams of chopped onion | = | 0.327 US cup |
18 grams of chopped onion | = | 0.346 US cup |
19 grams of chopped onion | = | 0.365 US cup |
20 grams of chopped onion | = | 0.384 US cup |
21 grams of chopped onion | = | 0.403 US cup |
22 grams of chopped onion | = | 0.423 US cup |
23 grams of chopped onion | = | 0.442 US cup |
24 grams of chopped onion | = | 0.461 US cup |
Note: some values may be rounded.
FAQs on chopped onion volume to weight conversion
15 grams of chopped onion equals how many US cups?
15 grams of chopped onion is equivalent 0.288 ( ~
How much is 0.288 US cup of chopped onion in grams?
0.288 US cup of chopped onion equals 15 grams.
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.
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