15 Grams of Graham Flour to Cups Conversion
Questions: How many US cups of graham flour in 15 grams? How much are 15 grams of graham flour in cups?
The answer is: 15 grams of graham flour is equivalent to 0.106 US cups(*)
'Weight' to Volume Converter
Grams of graham flour to US cups Chart
Grams of graham flour to US cups | ||
---|---|---|
6 grams of graham flour | = | 0.0423 US cups |
7 grams of graham flour | = | 0.0493 US cups |
8 grams of graham flour | = | 0.0564 US cups |
9 grams of graham flour | = | 0.0634 US cups |
10 grams of graham flour | = | 0.0704 US cups |
11 grams of graham flour | = | 0.0775 US cups |
12 grams of graham flour | = | 0.0845 US cups |
13 grams of graham flour | = | 0.0916 US cups |
14 grams of graham flour | = | 0.0986 US cups |
15 grams of graham flour | = | 0.106 US cups |
Grams of graham flour to US cups | ||
---|---|---|
15 grams of graham flour | = | 0.106 US cups |
16 grams of graham flour | = | 0.113 US cups |
17 grams of graham flour | = | 0.12 US cups |
18 grams of graham flour | = | 0.127 US cups |
19 grams of graham flour | = | 0.134 US cups |
20 grams of graham flour | = | 0.141 US cups |
21 grams of graham flour | = | 0.148 US cups |
22 grams of graham flour | = | 0.155 US cups |
23 grams of graham flour | = | 0.162 US cups |
24 grams of graham flour | = | 0.169 US cups |
Note: some values may be rounded.
FAQs on graham flour volume to weight conversion
15 grams of graham flour equals how many US cups?
15 grams of graham flour is equivalent 0.106 US cups.
How much is 0.106 US cups of graham flour in grams?
0.106 US cups of graham flour equals 15 grams.
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.
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