15 Grams of Icing Sugar to Cups Conversion

Questions: How many US cups of icing sugar in 15 grams? How much are 15 grams of icing sugar in cups?

The answer is: 15 grams of icing sugar is equivalent to 0.12 US cup(*)

'Weight' to Volume Converter

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Results
15 grams of icing sugar equals 0.12 US cup.
(*) To be more precise, 15 grams of icing sugar is equal to 0.12008 US cup. All figures are approximate.

Grams of icing sugar to US cups Chart

Grams of icing sugar to US cups
6 grams of icing sugar = 0.048 US cup
7 grams of icing sugar = 0.056 US cup
8 grams of icing sugar = 0.064 US cup
9 grams of icing sugar = 0.072 US cup
10 grams of icing sugar = 0.0801 US cup
11 grams of icing sugar = 0.0881 US cup
12 grams of icing sugar = 0.0961 US cup
13 grams of icing sugar = 0.104 US cup
14 grams of icing sugar = 0.112 US cup
15 grams of icing sugar = 0.12 US cup
Grams of icing sugar to US cups
15 grams of icing sugar = 0.12 US cup
16 grams of icing sugar = 0.128 US cup
17 grams of icing sugar = 0.136 US cup
18 grams of icing sugar = 0.144 US cup
19 grams of icing sugar = 0.152 US cup
20 grams of icing sugar = 0.16 US cup
21 grams of icing sugar = 0.168 US cup
22 grams of icing sugar = 0.176 US cup
23 grams of icing sugar = 0.184 US cup
24 grams of icing sugar = 0.192 US cup

Note: some values may be rounded.

FAQs on icing sugar volume to weight conversion

15 grams of icing sugar equals how many US cups?

15 grams of icing sugar is equivalent 0.12 US cup.

How much is 0.12 US cup of icing sugar in grams?

0.12 US cup of icing sugar equals 15 grams.

Weight to Volume Conversions - Cooking Ingredients

References:

  1. Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

Disclaimer

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