15 Grams of Milk Powder to Cups Conversion

Questions: How many US cups of milk powder in 15 grams? How much are 15 grams of milk powder in cups?

The answer is: 15 grams of milk powder is equivalent to 0.12 US cup(*)

'Weight' to Volume Converter

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Results
15 grams of milk powder equals 0.12 US cup.
(*) To be more precise, 15 grams of milk powder is equal to 0.12008 US cup. All figures are approximate.

Grams of milk powder to US cups Chart

Grams of milk powder to US cups
6 grams of milk powder = 0.048 US cup
7 grams of milk powder = 0.056 US cup
8 grams of milk powder = 0.064 US cup
9 grams of milk powder = 0.072 US cup
10 grams of milk powder = 0.0801 US cup
11 grams of milk powder = 0.0881 US cup
12 grams of milk powder = 0.0961 US cup
13 grams of milk powder = 0.104 US cup
14 grams of milk powder = 0.112 US cup
15 grams of milk powder = 0.12 US cup
Grams of milk powder to US cups
15 grams of milk powder = 0.12 US cup
16 grams of milk powder = 0.128 US cup
17 grams of milk powder = 0.136 US cup
18 grams of milk powder = 0.144 US cup
19 grams of milk powder = 0.152 US cup
20 grams of milk powder = 0.16 US cup
21 grams of milk powder = 0.168 US cup
22 grams of milk powder = 0.176 US cup
23 grams of milk powder = 0.184 US cup
24 grams of milk powder = 0.192 US cup

Note: some values may be rounded.

FAQs on milk powder volume to weight conversion

15 grams of milk powder equals how many US cups?

15 grams of milk powder is equivalent 0.12 US cup.

How much is 0.12 US cup of milk powder in grams?

0.12 US cup of milk powder equals 15 grams.

Weight to Volume Conversions - Cooking Ingredients

References:

  1. Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

Disclaimer

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