15 Grams of Packed Rocket to Cups Conversion
Questions: How many US cups of packed rocket in 15 grams? How much are 15 grams of packed rocket in cups?
The answer is: 15 grams of packed rocket is equivalent to 0.598 ( ~
'Weight' to Volume Converter
Grams of packed rocket to US cups Chart
Grams of packed rocket to US cups | ||
---|---|---|
6 grams of packed rocket | = | 0.239 US cup |
7 grams of packed rocket | = | 0.279 US cup |
8 grams of packed rocket | = | 0.319 US cup |
9 grams of packed rocket | = | 0.359 US cup |
10 grams of packed rocket | = | 0.399 US cup |
11 grams of packed rocket | = | 0.439 US cup |
12 grams of packed rocket | = | 0.479 US cup |
13 grams of packed rocket | = | 0.518 US cup |
14 grams of packed rocket | = | 0.558 US cup |
15 grams of packed rocket | = | 0.598 US cup |
Grams of packed rocket to US cups | ||
---|---|---|
15 grams of packed rocket | = | 0.598 US cup |
16 grams of packed rocket | = | 0.638 US cup |
17 grams of packed rocket | = | 0.678 US cup |
18 grams of packed rocket | = | 0.718 US cup |
19 grams of packed rocket | = | 0.758 US cup |
20 grams of packed rocket | = | 0.798 US cup |
21 grams of packed rocket | = | 0.837 US cup |
22 grams of packed rocket | = | 0.877 US cup |
23 grams of packed rocket | = | 0.917 US cup |
24 grams of packed rocket | = | 0.957 US cup |
Note: some values may be rounded.
FAQs on packed rocket volume to weight conversion
15 grams of packed rocket equals how many US cups?
15 grams of packed rocket is equivalent 0.598 ( ~
How much is 0.598 US cup of packed rocket in grams?
0.598 US cup of packed rocket equals 15 grams.
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.