15 Grams of Semolina to Tablespoons Conversion

Questions: How many US tablespoons of semolina in 15 grams? How much are 15 grams of semolina in tablespoons?

The answer is: 15 grams of semolina is equivalent to 1.33 ( ~ 1 1/4) US tablespoons(*)

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Results

15 grams of semolina equals 1.33 ( ~ 1 1/4) US tablespoons.
(*) To be more precise, 15 grams of semolina is equal to 1.333 US tablespoons. All figures are approximate.

Grams of semolina to US tablespoons Chart

Grams of semolina to US tablespoons
6 grams of semolina = 0.533 US tablespoons
7 grams of semolina = 0.622 US tablespoons
8 grams of semolina = 0.711 US tablespoons
9 grams of semolina = 0.8 US tablespoons
10 grams of semolina = 0.889 US tablespoons
11 grams of semolina = 0.978 US tablespoons
12 grams of semolina = 1.07 US tablespoons
13 grams of semolina = 1.16 US tablespoons
14 grams of semolina = 1.24 US tablespoons
15 grams of semolina = 1.33 US tablespoons
Grams of semolina to US tablespoons
15 grams of semolina = 1.33 US tablespoons
16 grams of semolina = 1.42 US tablespoons
17 grams of semolina = 1.51 US tablespoons
18 grams of semolina = 1.6 US tablespoons
19 grams of semolina = 1.69 US tablespoons
20 grams of semolina = 1.78 US tablespoons
21 grams of semolina = 1.87 US tablespoons
22 grams of semolina = 1.96 US tablespoons
23 grams of semolina = 2.04 US tablespoons
24 grams of semolina = 2.13 US tablespoons

Note: some values may be rounded.

FAQs on semolina volume to weight conversion

15 grams of semolina equals how many US tablespoons?

15 grams of semolina is equivalent 1.33 ( ~ 1 1/4) US tablespoons.

How much is 1.33 US tablespoons of semolina in grams?

1.33 US tablespoons of semolina equals 15 grams.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

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