16 Lb of Golden Syrup to Cups Conversion
Questions: How many US cups of golden syrup in 16 pounds? How much are 16 lb of golden syrup in cups?
The answer is: 16 pounds of golden syrup is equivalent to 20.7 ( ~ 20
'Weight' to Volume Converter
Pounds of golden syrup to US cups Chart
Pounds of golden syrup to US cups | ||
---|---|---|
7 pounds of golden syrup | = | 9.07 US cups |
8 pounds of golden syrup | = | 10.4 US cups |
9 pounds of golden syrup | = | 11.7 US cups |
10 pounds of golden syrup | = | 13 US cups |
11 pounds of golden syrup | = | 14.3 US cups |
12 pounds of golden syrup | = | 15.6 US cups |
13 pounds of golden syrup | = | 16.9 US cups |
14 pounds of golden syrup | = | 18.1 US cups |
15 pounds of golden syrup | = | 19.4 US cups |
16 pounds of golden syrup | = | 20.7 US cups |
Pounds of golden syrup to US cups | ||
---|---|---|
16 pounds of golden syrup | = | 20.7 US cups |
17 pounds of golden syrup | = | 22 US cups |
18 pounds of golden syrup | = | 23.3 US cups |
19 pounds of golden syrup | = | 24.6 US cups |
20 pounds of golden syrup | = | 25.9 US cups |
21 pounds of golden syrup | = | 27.2 US cups |
22 pounds of golden syrup | = | 28.5 US cups |
23 pounds of golden syrup | = | 29.8 US cups |
24 pounds of golden syrup | = | 31.1 US cups |
25 pounds of golden syrup | = | 32.4 US cups |
Note: some values may be rounded.
FAQs on golden syrup volume to weight conversion
16 pounds of golden syrup equals how many US cups?
16 pounds of golden syrup is equivalent 20.7 ( ~ 20
How much is 20.7 US cups of golden syrup in pounds?
20.7 US cups of golden syrup equals 16 ( ~ 16) pounds.
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.