16 Lb of Wheatgerm to Cups Conversion

Questions: How many US cups of wheatgerm in 16 pounds? How much are 16 lb of wheatgerm in cups?

The answer is: 16 pounds of wheatgerm is equivalent to 87.4 ( ~ 87 1/2) US cups(*)

'Weight' to Volume Converter

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Results
16 pounds of wheatgerm equals 87.4 ( ~ 87 1/2) US cups.
(*) To be more precise, 16 pounds of wheatgerm is equal to 87.395 US cups. All figures are approximate.

Pounds of wheatgerm to US cups Chart

Pounds of wheatgerm to US cups
7 pounds of wheatgerm = 38.2 US cups
8 pounds of wheatgerm = 43.7 US cups
9 pounds of wheatgerm = 49.2 US cups
10 pounds of wheatgerm = 54.6 US cups
11 pounds of wheatgerm = 60.1 US cups
12 pounds of wheatgerm = 65.5 US cups
13 pounds of wheatgerm = 71 US cups
14 pounds of wheatgerm = 76.5 US cups
15 pounds of wheatgerm = 81.9 US cups
16 pounds of wheatgerm = 87.4 US cups
Pounds of wheatgerm to US cups
16 pounds of wheatgerm = 87.4 US cups
17 pounds of wheatgerm = 92.9 US cups
18 pounds of wheatgerm = 98.3 US cups
19 pounds of wheatgerm = 104 US cups
20 pounds of wheatgerm = 109 US cups
21 pounds of wheatgerm = 115 US cups
22 pounds of wheatgerm = 120 US cups
23 pounds of wheatgerm = 126 US cups
24 pounds of wheatgerm = 131 US cups
25 pounds of wheatgerm = 137 US cups

Note: some values may be rounded.

FAQs on wheatgerm volume to weight conversion

16 pounds of wheatgerm equals how many US cups?

16 pounds of wheatgerm is equivalent 87.4 ( ~ 87 1/2) US cups.

How much is 87.4 US cups of wheatgerm in pounds?

87.4 US cups of wheatgerm equals 16 ( ~ 16) pounds.

Weight to Volume Conversions - Cooking Ingredients

References:

  1. Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

Disclaimer

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