16 Ounces of Margarine to Cups Conversion

Questions: How many US cups of margarine in 16 ounces? How much are 16 ounces of margarine in cups?

The answer is: 16 ounces of margarine is equivalent to 1.81 ( ~ 1 ³/₄) US cups^(*)

'Weight' to Volume Converter

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Results
16 ounces of margarine equals 1.81 ( ~ 1 ³/₄) US cups.
(*) To be more precise, 16 ounces of margarine is equal to 1.8138 US cups. All figures are approximate.
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Ounces of margarine to US cups Chart

Ounces of margarine to US cups
7 ounces of margarine	=	0.794 US cups
8 ounces of margarine	=	0.907 US cups
9 ounces of margarine	=	1.02 US cups
10 ounces of margarine	=	1.13 US cups
11 ounces of margarine	=	1.25 US cups
12 ounces of margarine	=	1.36 US cups
13 ounces of margarine	=	1.47 US cups
14 ounces of margarine	=	1.59 US cups
15 ounces of margarine	=	1.7 US cups
16 ounces of margarine	=	1.81 US cups

Ounces of margarine to US cups
16 ounces of margarine	=	1.81 US cups
17 ounces of margarine	=	1.93 US cups
18 ounces of margarine	=	2.04 US cups
19 ounces of margarine	=	2.15 US cups
20 ounces of margarine	=	2.27 US cups
21 ounces of margarine	=	2.38 US cups
22 ounces of margarine	=	2.49 US cups
23 ounces of margarine	=	2.61 US cups
24 ounces of margarine	=	2.72 US cups
25 ounces of margarine	=	2.83 US cups

Note: some values may be rounded.

FAQs on margarine volume to weight conversion

16 ounces of margarine equals how many US cups?

16 ounces of margarine is equivalent 1.81 ( ~ 1 ³/₄) US cups.

How much is 1.81 US cups of margarine in ounces?

1.81 US cups of margarine equals 16 ( ~ 16) ounces.

Weight to Volume Conversions - Cooking Ingredients

References:

Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.