16 Pounds of Dried Apples to Cups Conversion
Questions: How many US cups of dried apples in 16 pounds? How much are 16 pounds of dried apples in cups?
The answer is: 16 pounds of dried apples is equivalent to 61.5 ( ~ 61
'Weight' to Volume Converter
Pounds of dried apples to US cups Chart
Pounds of dried apples to US cups | ||
---|---|---|
7 pounds of dried apples | = | 26.9 US cups |
8 pounds of dried apples | = | 30.7 US cups |
9 pounds of dried apples | = | 34.6 US cups |
10 pounds of dried apples | = | 38.4 US cups |
11 pounds of dried apples | = | 42.3 US cups |
12 pounds of dried apples | = | 46.1 US cups |
13 pounds of dried apples | = | 49.9 US cups |
14 pounds of dried apples | = | 53.8 US cups |
15 pounds of dried apples | = | 57.6 US cups |
16 pounds of dried apples | = | 61.5 US cups |
Pounds of dried apples to US cups | ||
---|---|---|
16 pounds of dried apples | = | 61.5 US cups |
17 pounds of dried apples | = | 65.3 US cups |
18 pounds of dried apples | = | 69.2 US cups |
19 pounds of dried apples | = | 73 US cups |
20 pounds of dried apples | = | 76.8 US cups |
21 pounds of dried apples | = | 80.7 US cups |
22 pounds of dried apples | = | 84.5 US cups |
23 pounds of dried apples | = | 88.4 US cups |
24 pounds of dried apples | = | 92.2 US cups |
25 pounds of dried apples | = | 96.1 US cups |
Note: some values may be rounded.
FAQs on dried apples volume to weight conversion
16 pounds of dried apples equals how many US cups?
16 pounds of dried apples is equivalent 61.5 ( ~ 61
How much is 61.5 US cups of dried apples in pounds?
61.5 US cups of dried apples equals 16 ( ~ 16) pounds.
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.