2/3 Pounds of Bulgur to Cups Conversion

Questions: How many US cups of bulgur in 2/3 pounds? How much is 2/3 pounds of bulgur in cups?

The answer is: 2/3 pounds of bulgur is equivalent to 1.59 ( ~ 1 1/2) US cups(*)

'Weight' to Volume Converter

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Results
2/3 pounds of bulgur equals 1.59 ( ~ 1 1/2) US cups.
(*) To be more precise, 2/3 pounds of bulgur is equal to 1.5918 US cups. All figures are approximate.

Pounds of bulgur to US cups Chart

Pounds of bulgur to US cups
0.5767 pounds of bulgur = 1.38 US cups
0.5867 pounds of bulgur = 1.4 US cups
0.5967 pounds of bulgur = 1.42 US cups
0.6067 pounds of bulgur = 1.45 US cups
0.6167 pounds of bulgur = 1.47 US cups
0.6267 pounds of bulgur = 1.5 US cups
0.6367 pounds of bulgur = 1.52 US cups
0.6467 pounds of bulgur = 1.54 US cups
0.6567 pounds of bulgur = 1.57 US cups
0.667 pounds of bulgur = 1.59 US cups
Pounds of bulgur to US cups
0.667 pounds of bulgur = 1.59 US cups
0.6767 pounds of bulgur = 1.62 US cups
0.6867 pounds of bulgur = 1.64 US cups
0.6967 pounds of bulgur = 1.66 US cups
0.7067 pounds of bulgur = 1.69 US cups
0.7167 pounds of bulgur = 1.71 US cups
0.7267 pounds of bulgur = 1.74 US cups
0.7367 pounds of bulgur = 1.76 US cups
0.7467 pounds of bulgur = 1.78 US cups
0.7567 pounds of bulgur = 1.81 US cups

Note: some values may be rounded.

FAQs on bulgur volume to weight conversion

2/3 pounds of bulgur equals how many US cups?

2/3 pounds of bulgur is equivalent 1.59 ( ~ 1 1/2) US cups.

How much is 1.59 US cups of bulgur in pounds?

1.59 US cups of bulgur equals 2/3 ( ~ 3/4) pounds.

Weight to Volume Conversions - Cooking Ingredients

References:

  1. Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

Disclaimer

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