2 Grams of Icing Sugar to Cups Conversion
Questions: How many US cups of icing sugar in 2 grams? How much are 2 grams of icing sugar in cups?
The answer is: 2 grams of icing sugar is equivalent to 0.016 US cups(*)
'Weight' to Volume Converter
Grams of icing sugar to US cups Chart
Grams of icing sugar to US cups | ||
---|---|---|
1.1 grams of icing sugar | = | 0.00881 US cups |
1 1/5 grams of icing sugar | = | 0.00961 US cups |
1.3 grams of icing sugar | = | 0.0104 US cups |
1.4 grams of icing sugar | = | 0.0112 US cups |
1 1/2 grams of icing sugar | = | 0.012 US cups |
1.6 grams of icing sugar | = | 0.0128 US cups |
1.7 grams of icing sugar | = | 0.0136 US cups |
1.8 grams of icing sugar | = | 0.0144 US cups |
1.9 grams of icing sugar | = | 0.0152 US cups |
2 grams of icing sugar | = | 0.016 US cups |
Grams of icing sugar to US cups | ||
---|---|---|
2 grams of icing sugar | = | 0.016 US cups |
2.1 grams of icing sugar | = | 0.0168 US cups |
2 1/5 grams of icing sugar | = | 0.0176 US cups |
2.3 grams of icing sugar | = | 0.0184 US cups |
2.4 grams of icing sugar | = | 0.0192 US cups |
2 1/2 grams of icing sugar | = | 0.02 US cups |
2.6 grams of icing sugar | = | 0.0208 US cups |
2.7 grams of icing sugar | = | 0.0216 US cups |
2.8 grams of icing sugar | = | 0.0224 US cups |
2.9 grams of icing sugar | = | 0.0232 US cups |
Note: some values may be rounded.
FAQs on icing sugar volume to weight conversion
2 grams of icing sugar equals how many US cups?
2 grams of icing sugar is equivalent 0.016 US cups.
How much is 0.016 US cups of icing sugar in grams?
0.016 US cups of icing sugar equals 2 grams.
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.