2 Grams of Raisins to Ml Conversion

Questions: How many milliliters of raisins in 2 grams? How much are 2 grams of raisins in ml?

The answer is: 2 grams of raisins is equivalent to 2.98 milliliters^(*)

'Weight' to Volume Converter

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Results
2 grams of raisins equals 2.98 milliliters.
(*) To be more precise, 2 grams of raisins is equal to 2.9762 milliliters. All figures are approximate.
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Grams of raisins to milliliters Chart

Grams of raisins to milliliters
1.1 grams of raisins	=	1.64 milliliters
1 ¹/₅ grams of raisins	=	1.79 milliliters
1.3 grams of raisins	=	1.93 milliliters
1.4 grams of raisins	=	2 ¹/₁₂ milliliters
1 ¹/₂ grams of raisins	=	2.23 milliliters
1.6 grams of raisins	=	2.38 milliliters
1.7 grams of raisins	=	2.53 milliliters
1.8 grams of raisins	=	2.68 milliliters
1.9 grams of raisins	=	2.83 milliliters
2 grams of raisins	=	2.98 milliliters

Grams of raisins to milliliters
2 grams of raisins	=	2.98 milliliters
2.1 grams of raisins	=	3 ¹/₈ milliliters
2 ¹/₅ grams of raisins	=	3.27 milliliters
2.3 grams of raisins	=	3.42 milliliters
2.4 grams of raisins	=	3.57 milliliters
2 ¹/₂ grams of raisins	=	3.72 milliliters
2.6 grams of raisins	=	3.87 milliliters
2.7 grams of raisins	=	4.02 milliliters
2.8 grams of raisins	=	4 ¹/₆ milliliters
2.9 grams of raisins	=	4.32 milliliters

Note: some values may be rounded.

FAQs on raisins volume to weight conversion

2 grams of raisins equals how many milliliters?

2 grams of raisins is equivalent 2.98 milliliters.

How much is 2.98 milliliters of raisins in grams?

2.98 milliliters of raisins equals 2 grams.

Weight to Volume Conversions - Cooking Ingredients

References:

Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.