2 Pounds of Bulgur to Ml Conversion

Questions: How many milliliters of bulgur in 2 pounds? How much are 2 pounds of bulgur in ml?

The answer is: 2 pounds of bulgur is equivalent to 1130 milliliters(*)

'Weight' to Volume Converter

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Results
2 pounds of bulgur equals 1130 milliliters.
(*) To be more precise, 2 pounds of bulgur is equal to 1129.7 milliliters. All figures are approximate.

Pounds of bulgur to milliliters Chart

Pounds of bulgur to milliliters
1.1 pound of bulgur = 621 milliliters
1 1/5 pound of bulgur = 678 milliliters
1.3 pound of bulgur = 734 milliliters
1.4 pound of bulgur = 791 milliliters
1 1/2 pound of bulgur = 847 milliliters
1.6 pound of bulgur = 904 milliliters
1.7 pound of bulgur = 960 milliliters
1.8 pound of bulgur = 1020 milliliters
1.9 pound of bulgur = 1070 milliliters
2 pounds of bulgur = 1130 milliliters
Pounds of bulgur to milliliters
2 pounds of bulgur = 1130 milliliters
2.1 pounds of bulgur = 1190 milliliters
2 1/5 pounds of bulgur = 1240 milliliters
2.3 pounds of bulgur = 1300 milliliters
2.4 pounds of bulgur = 1360 milliliters
2 1/2 pounds of bulgur = 1410 milliliters
2.6 pounds of bulgur = 1470 milliliters
2.7 pounds of bulgur = 1530 milliliters
2.8 pounds of bulgur = 1580 milliliters
2.9 pounds of bulgur = 1640 milliliters

Note: some values may be rounded.

FAQs on bulgur volume to weight conversion

2 pounds of bulgur equals how many milliliters?

2 pounds of bulgur is equivalent 1130 milliliters.

How much is 1130 milliliters of bulgur in pounds?

1130 milliliters of bulgur equals 2 ( ~ 2) pounds.

Weight to Volume Conversions - Cooking Ingredients

References:

  1. Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

Disclaimer

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