20 Grams of Gelatin Powder to Cups Conversion

Questions: How many US cups of gelatin powder in 20 grams? How much are 20 grams of gelatin powder in cups?

The answer is: 20 grams of gelatin powder is equivalent to 0.133 ( ~ 1/4) US cups(*)

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Results

20 grams of gelatin powder equals 0.133 ( ~ 1/4) US cups.
(*) To be more precise, 20 grams of gelatin powder is equal to 0.13334 US cups. All figures are approximate.

Grams of gelatin powder to US cups Chart

Grams of gelatin powder to US cups
11 grams of gelatin powder = 0.0733 US cups
12 grams of gelatin powder = 0.08 US cups
13 grams of gelatin powder = 0.0867 US cups
14 grams of gelatin powder = 0.0933 US cups
15 grams of gelatin powder = 0.1 US cups
16 grams of gelatin powder = 0.107 US cups
17 grams of gelatin powder = 0.113 US cups
18 grams of gelatin powder = 0.12 US cups
19 grams of gelatin powder = 0.127 US cups
20 grams of gelatin powder = 0.133 US cups
Grams of gelatin powder to US cups
20 grams of gelatin powder = 0.133 US cups
21 grams of gelatin powder = 0.14 US cups
22 grams of gelatin powder = 0.147 US cups
23 grams of gelatin powder = 0.153 US cups
24 grams of gelatin powder = 0.16 US cups
25 grams of gelatin powder = 0.167 US cups
26 grams of gelatin powder = 0.173 US cups
27 grams of gelatin powder = 0.18 US cups
28 grams of gelatin powder = 0.187 US cups
29 grams of gelatin powder = 0.193 US cups

Note: some values may be rounded.

FAQs on gelatin powder volume to weight conversion

20 grams of gelatin powder equals how many US cups?

20 grams of gelatin powder is equivalent 0.133 ( ~ 1/4) US cups.

How much is 0.133 US cups of gelatin powder in grams?

0.133 US cups of gelatin powder equals 20 grams.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

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