25 Grams of Dry Lentils to Teaspoons Conversion

Questions: How many US teaspoons of dry lentils in 25 grams? How much are 25 grams of dry lentils in teaspoons?

The answer is: 25 grams of dry lentils is equivalent to 6 ( ~ 6) US teaspoons(*)

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Results

25 grams of dry lentils equals 6 ( ~ 6) US teaspoons.
(*) To be more precise, 25 grams of dry lentils is equal to 6.0025 US teaspoons. All figures are approximate.

Grams of dry lentils to US teaspoons Chart

Grams of dry lentils to US teaspoons
16 grams of dry lentils = 3.84 US teaspoons
17 grams of dry lentils = 4.08 US teaspoons
18 grams of dry lentils = 4.32 US teaspoons
19 grams of dry lentils = 4.56 US teaspoons
20 grams of dry lentils = 4.8 US teaspoons
21 grams of dry lentils = 5.04 US teaspoons
22 grams of dry lentils = 5.28 US teaspoons
23 grams of dry lentils = 5.52 US teaspoons
24 grams of dry lentils = 5.76 US teaspoons
25 grams of dry lentils = 6 US teaspoons
Grams of dry lentils to US teaspoons
25 grams of dry lentils = 6 US teaspoons
26 grams of dry lentils = 6.24 US teaspoons
27 grams of dry lentils = 6.48 US teaspoons
28 grams of dry lentils = 6.72 US teaspoons
29 grams of dry lentils = 6.96 US teaspoons
30 grams of dry lentils = 7.2 US teaspoons
31 grams of dry lentils = 7.44 US teaspoons
32 grams of dry lentils = 7.68 US teaspoons
33 grams of dry lentils = 7.92 US teaspoons
34 grams of dry lentils = 8.16 US teaspoons

Note: some values may be rounded.

FAQs on dry lentils volume to weight conversion

25 grams of dry lentils equals how many US teaspoons?

25 grams of dry lentils is equivalent 6 ( ~ 6) US teaspoons.

How much is 6 US teaspoons of dry lentils in grams?

6 US teaspoons of dry lentils equals 25 grams.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

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