25 Grams of Powdered Onion to Cups Conversion

Questions: How many US cups of powdered onion in 25 grams? How much are 25 grams of powdered onion in cups?

The answer is: 25 grams of powdered onion is equivalent to 0.264 ( ~ 1/4) US cup(*)

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Results

25 grams of powdered onion equals 0.264 ( ~ 1/4) US cup.
(*) To be more precise, 25 grams of powdered onion is equal to 0.26417 US cup. All figures are approximate.

Grams of powdered onion to US cups Chart

Grams of powdered onion to US cups
16 grams of powdered onion = 0.169 US cup
17 grams of powdered onion = 0.18 US cup
18 grams of powdered onion = 0.19 US cup
19 grams of powdered onion = 0.201 US cup
20 grams of powdered onion = 0.211 US cup
21 grams of powdered onion = 0.222 US cup
22 grams of powdered onion = 0.232 US cup
23 grams of powdered onion = 0.243 US cup
24 grams of powdered onion = 0.254 US cup
25 grams of powdered onion = 0.264 US cup
Grams of powdered onion to US cups
25 grams of powdered onion = 0.264 US cup
26 grams of powdered onion = 0.275 US cup
27 grams of powdered onion = 0.285 US cup
28 grams of powdered onion = 0.296 US cup
29 grams of powdered onion = 0.306 US cup
30 grams of powdered onion = 0.317 US cup
31 grams of powdered onion = 0.328 US cup
32 grams of powdered onion = 0.338 US cup
33 grams of powdered onion = 0.349 US cup
34 grams of powdered onion = 0.359 US cup

Note: some values may be rounded.

FAQs on powdered onion volume to weight conversion

25 grams of powdered onion equals how many US cups?

25 grams of powdered onion is equivalent 0.264 ( ~ 1/4) US cup.

How much is 0.264 US cup of powdered onion in grams?

0.264 US cup of powdered onion equals 25 grams.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

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