25 Grams of Shea Butter to Cups Conversion

Questions: How many US cups of shea butter in 25 grams? How much are 25 grams of shea butter in cups?

The answer is: 25 grams of shea butter is equivalent to 0.117 US cup^(*)

'Weight' to Volume Converter

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Results
25 grams of shea butter equals 0.117 US cup.
(*) To be more precise, 25 grams of shea butter is equal to 0.11663 US cup. All figures are approximate.
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Grams of shea butter to US cups Chart

Grams of shea butter to US cups
16 grams of shea butter	=	0.0746 US cup
17 grams of shea butter	=	0.0793 US cup
18 grams of shea butter	=	0.084 US cup
19 grams of shea butter	=	0.0886 US cup
20 grams of shea butter	=	0.0933 US cup
21 grams of shea butter	=	0.098 US cup
22 grams of shea butter	=	0.103 US cup
23 grams of shea butter	=	0.107 US cup
24 grams of shea butter	=	0.112 US cup
25 grams of shea butter	=	0.117 US cup

Grams of shea butter to US cups
25 grams of shea butter	=	0.117 US cup
26 grams of shea butter	=	0.121 US cup
27 grams of shea butter	=	0.126 US cup
28 grams of shea butter	=	0.131 US cup
29 grams of shea butter	=	0.135 US cup
30 grams of shea butter	=	0.14 US cup
31 grams of shea butter	=	0.145 US cup
32 grams of shea butter	=	0.149 US cup
33 grams of shea butter	=	0.154 US cup
34 grams of shea butter	=	0.159 US cup

Note: some values may be rounded.

FAQs on shea butter volume to weight conversion

25 grams of shea butter equals how many US cups?

25 grams of shea butter is equivalent 0.117 US cup.

How much is 0.117 US cup of shea butter in grams?

0.117 US cup of shea butter equals 25 grams.

Weight to Volume Conversions - Cooking Ingredients

References:

Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.