30 Grams of Chopped Apples to Cups Conversion

Questions: How many US cups of chopped apples in 30 grams? How much are 30 grams of chopped apples in cups?

The answer is: 30 grams of chopped apples is equivalent to 0.254 ( ~ 1/4) US cup(*)

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Results

30 grams of chopped apples equals 0.254 ( ~ 1/4) US cup.
(*) To be more precise, 30 grams of chopped apples is equal to 0.25411 US cup. All figures are approximate.

Grams of chopped apples to US cups Chart

Grams of chopped apples to US cups
21 grams of chopped apples = 0.178 US cup
22 grams of chopped apples = 0.186 US cup
23 grams of chopped apples = 0.195 US cup
24 grams of chopped apples = 0.203 US cup
25 grams of chopped apples = 0.212 US cup
26 grams of chopped apples = 0.22 US cup
27 grams of chopped apples = 0.229 US cup
28 grams of chopped apples = 0.237 US cup
29 grams of chopped apples = 0.246 US cup
30 grams of chopped apples = 0.254 US cup
Grams of chopped apples to US cups
30 grams of chopped apples = 0.254 US cup
31 grams of chopped apples = 0.263 US cup
32 grams of chopped apples = 0.271 US cup
33 grams of chopped apples = 0.28 US cup
34 grams of chopped apples = 0.288 US cup
35 grams of chopped apples = 0.296 US cup
36 grams of chopped apples = 0.305 US cup
37 grams of chopped apples = 0.313 US cup
38 grams of chopped apples = 0.322 US cup
39 grams of chopped apples = 0.33 US cup

Note: some values may be rounded.

FAQs on chopped apples volume to weight conversion

30 grams of chopped apples equals how many US cups?

30 grams of chopped apples is equivalent 0.254 ( ~ 1/4) US cup.

How much is 0.254 US cup of chopped apples in grams?

0.254 US cup of chopped apples equals 30 grams.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

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