35 Grams of Cheddar Cheese to Cups Conversion

Questions: How many US cups of cheddar cheese in 35 grams? How much are 35 grams of cheddar cheese in cups?

The answer is: 35 grams of cheddar cheese is equivalent to 0.149 ( ~ 1/4) US cup(*)

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Results

35 grams of cheddar cheese equals 0.149 ( ~ 1/4) US cup.
(*) To be more precise, 35 grams of cheddar cheese is equal to 0.14898 US cup. All figures are approximate.

Grams of cheddar cheese to US cups Chart

Grams of cheddar cheese to US cups
26 grams of cheddar cheese = 0.111 US cup
27 grams of cheddar cheese = 0.115 US cup
28 grams of cheddar cheese = 0.119 US cup
29 grams of cheddar cheese = 0.123 US cup
30 grams of cheddar cheese = 0.128 US cup
31 grams of cheddar cheese = 0.132 US cup
32 grams of cheddar cheese = 0.136 US cup
33 grams of cheddar cheese = 0.14 US cup
34 grams of cheddar cheese = 0.145 US cup
35 grams of cheddar cheese = 0.149 US cup
Grams of cheddar cheese to US cups
35 grams of cheddar cheese = 0.149 US cup
36 grams of cheddar cheese = 0.153 US cup
37 grams of cheddar cheese = 0.157 US cup
38 grams of cheddar cheese = 0.162 US cup
39 grams of cheddar cheese = 0.166 US cup
40 grams of cheddar cheese = 0.17 US cup
41 grams of cheddar cheese = 0.175 US cup
42 grams of cheddar cheese = 0.179 US cup
43 grams of cheddar cheese = 0.183 US cup
44 grams of cheddar cheese = 0.187 US cup

Note: some values may be rounded.

FAQs on cheddar cheese volume to weight conversion

35 grams of cheddar cheese equals how many US cups?

35 grams of cheddar cheese is equivalent 0.149 ( ~ 1/4) US cup.

How much is 0.149 US cup of cheddar cheese in grams?

0.149 US cup of cheddar cheese equals 35 grams.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

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