45 Grams of Chopped Apples to Cups Conversion

Questions: How many US cups of chopped apples in 45 grams? How much are 45 grams of chopped apples in cups?

The answer is: 45 grams of chopped apples is equivalent to 0.381 ( ~ 1/2) US cup(*)

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Results

45 grams of chopped apples equals 0.381 ( ~ 1/2) US cup.
(*) To be more precise, 45 grams of chopped apples is equal to 0.38117 US cup. All figures are approximate.

Grams of chopped apples to US cups Chart

Grams of chopped apples to US cups
36 grams of chopped apples = 0.305 US cup
37 grams of chopped apples = 0.313 US cup
38 grams of chopped apples = 0.322 US cup
39 grams of chopped apples = 0.33 US cup
40 grams of chopped apples = 0.339 US cup
41 grams of chopped apples = 0.347 US cup
42 grams of chopped apples = 0.356 US cup
43 grams of chopped apples = 0.364 US cup
44 grams of chopped apples = 0.373 US cup
45 grams of chopped apples = 0.381 US cup
Grams of chopped apples to US cups
45 grams of chopped apples = 0.381 US cup
46 grams of chopped apples = 0.39 US cup
47 grams of chopped apples = 0.398 US cup
48 grams of chopped apples = 0.407 US cup
49 grams of chopped apples = 0.415 US cup
50 grams of chopped apples = 0.424 US cup
51 grams of chopped apples = 0.432 US cup
52 grams of chopped apples = 0.44 US cup
53 grams of chopped apples = 0.449 US cup
54 grams of chopped apples = 0.457 US cup

Note: some values may be rounded.

FAQs on chopped apples volume to weight conversion

45 grams of chopped apples equals how many US cups?

45 grams of chopped apples is equivalent 0.381 ( ~ 1/2) US cup.

How much is 0.381 US cup of chopped apples in grams?

0.381 US cup of chopped apples equals 45 grams.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

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