5 Pounds of Ricotta to Ml Conversion
Questions: How many milliliters of ricotta in 5 pounds? How much are 5 pounds of ricotta in ml?
The answer is: 5 pounds of ricotta is equivalent to 2150 milliliters(*)
'Weight' to Volume Converter
Pounds of ricotta to milliliters Chart
Pounds of ricotta to milliliters | ||
---|---|---|
4.1 pounds of ricotta | = | 1760 milliliters |
4 1/5 pounds of ricotta | = | 1800 milliliters |
4.3 pounds of ricotta | = | 1850 milliliters |
4.4 pounds of ricotta | = | 1890 milliliters |
4 1/2 pounds of ricotta | = | 1930 milliliters |
4.6 pounds of ricotta | = | 1970 milliliters |
4.7 pounds of ricotta | = | 2020 milliliters |
4.8 pounds of ricotta | = | 2060 milliliters |
4.9 pounds of ricotta | = | 2100 milliliters |
5 pounds of ricotta | = | 2150 milliliters |
Pounds of ricotta to milliliters | ||
---|---|---|
5 pounds of ricotta | = | 2150 milliliters |
5.1 pounds of ricotta | = | 2190 milliliters |
5 1/5 pounds of ricotta | = | 2230 milliliters |
5.3 pounds of ricotta | = | 2270 milliliters |
5.4 pounds of ricotta | = | 2320 milliliters |
5 1/2 pounds of ricotta | = | 2360 milliliters |
5.6 pounds of ricotta | = | 2400 milliliters |
5.7 pounds of ricotta | = | 2450 milliliters |
5.8 pounds of ricotta | = | 2490 milliliters |
5.9 pounds of ricotta | = | 2530 milliliters |
Note: some values may be rounded.
FAQs on ricotta volume to weight conversion
5 pounds of ricotta equals how many milliliters?
5 pounds of ricotta is equivalent 2150 milliliters.
How much is 2150 milliliters of ricotta in pounds?
2150 milliliters of ricotta equals 5 ( ~ 5) pounds.
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.