50 Grams of Potato to Cups Conversion

Questions: How many US cups of potato in 50 grams? How much are 50 grams of potato in cups?

The answer is: 50 grams of potato is equivalent to 0.358 ( ~ 1/4) US cups(*)

'Weight' to Volume Converter

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weight ?Enter the amount of the mass measurement (weight). The calculator accepts fractional values such as: 1/2 (half), 1/3 (1 third), etc.
unit ? Choose the unit of mass (Kilogram, milligram, ounce, etc.)
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Results

50 grams of potato equals 0.358 ( ~ 1/4) US cups.
(*) To be more precise, 50 grams of potato is equal to 0.3582 US cups. All figures are approximate.

Grams of potato to US cups Chart

Grams of potato to US cups
41 grams of potato = 0.294 US cups
42 grams of potato = 0.301 US cups
43 grams of potato = 0.308 US cups
44 grams of potato = 0.315 US cups
45 grams of potato = 0.322 US cups
46 grams of potato = 0.33 US cups
47 grams of potato = 0.337 US cups
48 grams of potato = 0.344 US cups
49 grams of potato = 0.351 US cups
50 grams of potato = 0.358 US cups
Grams of potato to US cups
50 grams of potato = 0.358 US cups
51 grams of potato = 0.365 US cups
52 grams of potato = 0.373 US cups
53 grams of potato = 0.38 US cups
54 grams of potato = 0.387 US cups
55 grams of potato = 0.394 US cups
56 grams of potato = 0.401 US cups
57 grams of potato = 0.408 US cups
58 grams of potato = 0.416 US cups
59 grams of potato = 0.423 US cups

Note: some values may be rounded.

FAQs on potato volume to weight conversion

50 grams of potato equals how many US cups?

50 grams of potato is equivalent 0.358 ( ~ 1/4) US cups.

How much is 0.358 US cups of potato in grams?

0.358 US cups of potato equals 50 grams.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

Disclaimer

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