A Eighth Pounds of Dry Pasta to Cups Conversion

Questions: How many US cups of dry pasta in A Eighth pounds? How much is A Eighth pounds of dry pasta in cups?

The answer is: a eighth pounds of dry pasta is equivalent to 0.567 ( ~ 1/2) US cups(*)

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Results

A eighth pounds of dry pasta equals 0.567 ( ~ 1/2) US cups.
(*) To be more precise, a eighth pounds of dry pasta is equal to 0.56656 US cups. All figures are approximate.

Pounds of dry pasta to US cups Chart

Pounds of dry pasta to US cups
0.035 pounds of dry pasta = 0.159 US cups
0.045 pounds of dry pasta = 0.204 US cups
0.055 pounds of dry pasta = 0.249 US cups
0.065 pounds of dry pasta = 0.295 US cups
0.075 pounds of dry pasta = 0.34 US cups
0.085 pounds of dry pasta = 0.385 US cups
0.095 pounds of dry pasta = 0.431 US cups
0.105 pounds of dry pasta = 0.476 US cups
0.115 pounds of dry pasta = 0.521 US cups
1/8 pounds of dry pasta = 0.567 US cups
Pounds of dry pasta to US cups
1/8 pounds of dry pasta = 0.567 US cups
0.135 pounds of dry pasta = 0.612 US cups
0.145 pounds of dry pasta = 0.657 US cups
0.155 pounds of dry pasta = 0.703 US cups
0.165 pounds of dry pasta = 0.748 US cups
0.175 pounds of dry pasta = 0.793 US cups
0.185 pounds of dry pasta = 0.839 US cups
0.195 pounds of dry pasta = 0.884 US cups
0.205 pounds of dry pasta = 0.929 US cups
0.215 pounds of dry pasta = 0.974 US cups

Note: some values may be rounded.

FAQs on dry pasta volume to weight conversion

A eighth pounds of dry pasta equals how many US cups?

A eighth pounds of dry pasta is equivalent 0.567 ( ~ 1/2) US cups.

How much is 0.567 US cups of dry pasta in pounds?

0.567 US cups of dry pasta equals a eighth ( ~ 1/4) pounds.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

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