A Fifth Lb of Bulgur to Cups Conversion

Questions: How many US cups of bulgur in A Fifth pounds? How much is A Fifth lb of bulgur in cups?

The answer is: a fifth pounds of bulgur is equivalent to 0.478 ( ~ ¹/₂) US cups^(*)

'Weight' to Volume Converter

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Results
A fifth pounds of bulgur equals 0.478 ( ~ ¹/₂) US cups.
(*) To be more precise, a fifth pounds of bulgur is equal to 0.47752 US cups. All figures are approximate.
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Pounds of bulgur to US cups Chart

Pounds of bulgur to US cups
0.11 pounds of bulgur	=	0.263 US cups
0.12 pounds of bulgur	=	0.287 US cups
0.13 pounds of bulgur	=	0.31 US cups
0.14 pounds of bulgur	=	0.334 US cups
0.15 pounds of bulgur	=	0.358 US cups
0.16 pounds of bulgur	=	0.382 US cups
0.17 pounds of bulgur	=	0.406 US cups
0.18 pounds of bulgur	=	0.43 US cups
0.19 pounds of bulgur	=	0.454 US cups
¹/₅ pounds of bulgur	=	0.478 US cups

Pounds of bulgur to US cups
¹/₅ pounds of bulgur	=	0.478 US cups
0.21 pounds of bulgur	=	0.501 US cups
0.22 pounds of bulgur	=	0.525 US cups
0.23 pounds of bulgur	=	0.549 US cups
0.24 pounds of bulgur	=	0.573 US cups
¹/₄ pounds of bulgur	=	0.597 US cups
0.26 pounds of bulgur	=	0.621 US cups
0.27 pounds of bulgur	=	0.645 US cups
0.28 pounds of bulgur	=	0.669 US cups
0.29 pounds of bulgur	=	0.692 US cups

Note: some values may be rounded.

FAQs on bulgur volume to weight conversion

A fifth pounds of bulgur equals how many US cups?

A fifth pounds of bulgur is equivalent 0.478 ( ~ ¹/₂) US cups.

How much is 0.478 US cups of bulgur in pounds?

0.478 US cups of bulgur equals a fifth ( ~ ¹/₄) pounds.

Weight to Volume Conversions - Cooking Ingredients

References:

Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.