A Fifth Pound of Ricotta to Ml Conversion
Questions: How many milliliters of ricotta in A Fifth pound? How much is A Fifth pound of ricotta in ml?
The answer is: a fifth pound of ricotta is equivalent to 85.8 milliliters(*)
'Weight' to Volume Converter
Pounds of ricotta to milliliters Chart
Pounds of ricotta to milliliters | ||
---|---|---|
0.11 pound of ricotta | = | 47.2 milliliters |
0.12 pound of ricotta | = | 51.5 milliliters |
0.13 pound of ricotta | = | 55.8 milliliters |
0.14 pound of ricotta | = | 60.1 milliliters |
0.15 pound of ricotta | = | 64.4 milliliters |
0.16 pound of ricotta | = | 68.7 milliliters |
0.17 pound of ricotta | = | 73 milliliters |
0.18 pound of ricotta | = | 77.2 milliliters |
0.19 pound of ricotta | = | 81.5 milliliters |
1/5 pound of ricotta | = | 85.8 milliliters |
Pounds of ricotta to milliliters | ||
---|---|---|
1/5 pound of ricotta | = | 85.8 milliliters |
0.21 pound of ricotta | = | 90.1 milliliters |
0.22 pound of ricotta | = | 94.4 milliliters |
0.23 pound of ricotta | = | 98.7 milliliters |
0.24 pound of ricotta | = | 103 milliliters |
1/4 pound of ricotta | = | 107 milliliters |
0.26 pound of ricotta | = | 112 milliliters |
0.27 pound of ricotta | = | 116 milliliters |
0.28 pound of ricotta | = | 120 milliliters |
0.29 pound of ricotta | = | 124 milliliters |
Note: some values may be rounded.
FAQs on ricotta volume to weight conversion
A fifth pound of ricotta equals how many milliliters?
A fifth pound of ricotta is equivalent 85.8 milliliters.
How much is 85.8 milliliters of ricotta in pounds?
85.8 milliliters of ricotta equals a fifth ( ~
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.
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