Half Pounds of Ricotta to Cups Conversion

Questions: How many US cups of ricotta in Half pounds? How much is Half pounds of ricotta in cups?

The answer is: half pounds of ricotta is equivalent to 0.907 ( ~ 1) US cups^(*)

'Weight' to Volume Converter

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Results
Half pounds of ricotta equals 0.907 ( ~ 1) US cups.
(*) To be more precise, half pounds of ricotta is equal to 0.90692 US cups. All figures are approximate.
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Pounds of ricotta to US cups Chart

Pounds of ricotta to US cups
0.41 pounds of ricotta	=	0.744 US cups
0.42 pounds of ricotta	=	0.762 US cups
0.43 pounds of ricotta	=	0.78 US cups
0.44 pounds of ricotta	=	0.798 US cups
0.45 pounds of ricotta	=	0.816 US cups
0.46 pounds of ricotta	=	0.834 US cups
0.47 pounds of ricotta	=	0.853 US cups
0.48 pounds of ricotta	=	0.871 US cups
0.49 pounds of ricotta	=	0.889 US cups
¹/₂ pounds of ricotta	=	0.907 US cups

Pounds of ricotta to US cups
¹/₂ pounds of ricotta	=	0.907 US cups
0.51 pounds of ricotta	=	0.925 US cups
0.52 pounds of ricotta	=	0.943 US cups
0.53 pounds of ricotta	=	0.961 US cups
0.54 pounds of ricotta	=	0.979 US cups
0.55 pounds of ricotta	=	0.998 US cups
0.56 pounds of ricotta	=	1.02 US cups
0.57 pounds of ricotta	=	1.03 US cups
0.58 pounds of ricotta	=	1.05 US cups
0.59 pounds of ricotta	=	1.07 US cups

Note: some values may be rounded.

FAQs on ricotta volume to weight conversion

Half pounds of ricotta equals how many US cups?

Half pounds of ricotta is equivalent 0.907 ( ~ 1) US cups.

How much is 0.907 US cups of ricotta in pounds?

0.907 US cups of ricotta equals half ( ~ ¹/₂) pounds.

Weight to Volume Conversions - Cooking Ingredients

References:

Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.