Two Pounds of Semolina to Ml Conversion
Questions: How many milliliters of semolina in Two pounds? How much are Two pounds of semolina in ml?
The answer is: two pounds of semolina is equivalent to 1190 milliliters(*)
'Weight' to Volume Converter
Pounds of semolina to milliliters Chart
Pounds of semolina to milliliters | ||
---|---|---|
1.1 pounds of semolina | = | 656 milliliters |
1 1/5 pounds of semolina | = | 715 milliliters |
1.3 pounds of semolina | = | 775 milliliters |
1.4 pounds of semolina | = | 834 milliliters |
1 1/2 pounds of semolina | = | 894 milliliters |
1.6 pounds of semolina | = | 954 milliliters |
1.7 pounds of semolina | = | 1010 milliliters |
1.8 pounds of semolina | = | 1070 milliliters |
1.9 pounds of semolina | = | 1130 milliliters |
2 pounds of semolina | = | 1190 milliliters |
Pounds of semolina to milliliters | ||
---|---|---|
2 pounds of semolina | = | 1190 milliliters |
2.1 pounds of semolina | = | 1250 milliliters |
2 1/5 pounds of semolina | = | 1310 milliliters |
2.3 pounds of semolina | = | 1370 milliliters |
2.4 pounds of semolina | = | 1430 milliliters |
2 1/2 pounds of semolina | = | 1490 milliliters |
2.6 pounds of semolina | = | 1550 milliliters |
2.7 pounds of semolina | = | 1610 milliliters |
2.8 pounds of semolina | = | 1670 milliliters |
2.9 pounds of semolina | = | 1730 milliliters |
Note: some values may be rounded.
FAQs on semolina volume to weight conversion
Two pounds of semolina equals how many milliliters?
Two pounds of semolina is equivalent 1190 milliliters.
How much is 1190 milliliters of semolina in pounds?
1190 milliliters of semolina equals two ( ~ 2) pounds.
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.
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