1/4 Cups of Buttermilk to Pounds Conversion
Question:
How many pounds of buttermilk in 1/4 US cups? How much is 1/4 cups of buttermilk in pounds?
The answer is:
1/4 US cups of buttermilk is equivalent to 0.133 ( ~
Volume to 'Weight' Converter
US cups of buttermilk to pounds Chart
US cups of buttermilk to pounds | ||
---|---|---|
0.16 US cups of buttermilk | = | 0.0854 pounds |
0.17 US cups of buttermilk | = | 0.0907 pounds |
0.18 US cups of buttermilk | = | 0.096 pounds |
0.19 US cups of buttermilk | = | 0.101 pounds |
1/5 US cups of buttermilk | = | 0.107 pounds |
0.21 US cups of buttermilk | = | 0.112 pounds |
0.22 US cups of buttermilk | = | 0.117 pounds |
0.23 US cups of buttermilk | = | 0.123 pounds |
0.24 US cups of buttermilk | = | 0.128 pounds |
1/4 US cups of buttermilk | = | 0.133 pounds |
US cups of buttermilk to pounds | ||
---|---|---|
1/4 US cups of buttermilk | = | 0.133 pounds |
0.26 US cups of buttermilk | = | 0.139 pounds |
0.27 US cups of buttermilk | = | 0.144 pounds |
0.28 US cups of buttermilk | = | 0.149 pounds |
0.29 US cups of buttermilk | = | 0.155 pounds |
0.3 US cups of buttermilk | = | 0.16 pounds |
0.31 US cups of buttermilk | = | 0.165 pounds |
0.32 US cups of buttermilk | = | 0.171 pounds |
0.33 US cups of buttermilk | = | 0.176 pounds |
0.34 US cups of buttermilk | = | 0.181 pounds |
Note: some values may be rounded.
FAQs on buttermilk weight to volume conversion
1/4 US cups of buttermilk equals how many pounds?
1/4 US cups of buttermilk is equivalent 0.133 ( ~
How much is 0.133 pounds of buttermilk in US cups?
0.133 pounds of buttermilk equals 1/4 ( ~
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.